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Sunday, March 03 14 / com

Updates on my research and expository papers, discussion of open problems, and other maths-related topics. By Terence Tao


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What volume of 2.0 M NaCl is required to prepare 150 mL of 0.10 M ...
Wednesday, April 04 14 /

Best Answer: a. 7.5 mL b/c .10 M means .10 mol/1L which in proportion is 0.10mol/1000mL=xmol/150mL which then means there are .015 moles of NaCl Then we set up a new ...

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What is the initial molarity in the diluted solution? - Yahoo!7 ...
Saturday, October 10 14 /

Best Answer: molarity= number of moles/ volume (in L) 3.0 ml of the 0.25% solution contain 3 * 0.25 / 100 / 180 = 4.17 e-5 mol divide this by 0.1 L to get 4.17 * 10 ...

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Wednesday, July 07 14 /

A 20.00 mL sample of 0.009873 mol/L oxalic acid was titrated with potassium permanganate. If 32.33 mL of a KMnO4 solution was required to reach the pink end point ...

NSS Mathematics in Action M2 Vol1 Full Solution Allulook4.com
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Monday, January 01 14 / com

To provide information, instruction, and clues to problems in math and science for Dr Daves students at Brown Mackie College

NSS Math in Action M2 (Vol 1, 2) Full Solution - ...
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Yahoo! Canada Answers - A mole of X reacts at a constant pressure ...
Tuesday, February 02 14 /

Best Answer: Given data H0 = -75.0 kJ Pressure, P = 43.0 atm = 43 atm * 101325 Pa/1 atm = 4356975 Pa = 4356975 N / m2 Volume change, V = 2.0 L - 5.0 L = -3.0 L ...

0.1 M HCL solution
Friday, January 01 14 / 0

Author: Topic: 0.1 M HCL solution (Read 15905 times) 0 Members and 1 Guest are viewing this topic.

How do I make a 10 millimolar solution of HCl (in 1 Litre of Water ...
Monday, April 04 14 /

Thanks for your answer Dr Buzz.. I calculated that at 1st but I need the HCl amount in mL. So i suspect im meant to use the V1 x M1 = V2 x M2 equation..

Yahoo! Answers - Sol. of 14.8M of NH3. How many mL of sol should ...
Thursday, January 01 14 /

Best Answer: M1V1=M2V2 14.8 * V1 = 0.25*100 V1 = 0.25*100/14.8 V1 = 1.689ml M1V1= M2V2 14.8*10 = M2*250 M2 = 14.8*10/250 M2 = 0.592M

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